Solve initial value problem explicitly:

1. y'= ye^-x, y(0)=1

2. y'= 5xe^-y, y(1)=1

1 answer

1. See
http://www.jiskha.com/display.cgi?id=1296694049

2. See
http://www.jiskha.com/display.cgi?id=1296697362
Similar Questions
  1. Solve the following initial value problem explicitly:y'= ye^-x , y(0)=1 How do you solve this problem? I'm really confused!
    1. answers icon 1 answer
  2. how would you solve for y in this problem:x=(y^2+3y)^(1/3) I got: y= x^3/y - 3 ? and for this problem: x= 1/[(y^2+3y-5)^3] I
    1. answers icon 0 answers
  3. how do I solve this problem 2x/2=(6-3y)/2?2x/2=(6-3y)/2? <b>I solved it for you in my initial answer. The 2 in the numerator
    1. answers icon 0 answers
    1. answers icon 3 answers
more similar questions