Unless you have a typo, this is a very easy problem
Your first equation says that y = x
your second equation means that y = x^2
This is only true at (0,0) and (1,1))
Now:
y = x is a straight line in quadrants 1 and three at 45 degrees to the x axis
y = x^2 is a parabola, facing up (holds water) with vertex at (0,0)
other points at
(-3,9),(-2,4), (-1,1) (0,0),(1,1),(2,4),(3,9)
Solve graphically.
x-y=0
y=x²
The reason I don't understand the question is the second equation with the x². How do I graph that? I'm not sure if I ever graphed with an exponent, and if I did, it was a long time ago.
Thanks!
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