take coommon 3 out from the equation. it will be 3(x+y) = 9; then x+y = 9/3 =3 ; then x = 3-y; replace the value of x with is i,e = 3(3-y +y] =9 = 9-3y+3y =9 then x= 9/9 =1 ; when x = 1 then y 3+3y = 9; then 3y = 9 -3 = 6 ; then y = 6/3 = 2; means x=1 and y = 2 ; = put the value of x and y in you equation it will be 3x1+3x2 = 9.
hope this is the way to find out. i am not a mathematician. May somebody else will come with different Idea. let us wait.
solve for y and x, please show steps
3x+3y=9
2 answers
to solve for x,
first, transpose all terms which does not contain x,, thus we have to transpose the term 3y to the right side of equation, but the sign must be the opposite:
3x + 3y = 9
3x = 9 - 3y *positive 3y becomes negative after transposing
after that, divide the numerical coefficient of x (which is 3) to all terms in the equation to get x:
(3x)/3 = (9)/3 - (3y)/3
x = 3 - y
the steps to solve for y is the same as that of solving for x,, of course, terms that should be transposed to other side of equation must not contain y,, therefore:
3x + 3y = 9 *transpose.
3y = 9 - 3x *then divide by num. coefficient of y (which is 3)
y = 3 - y
so there,, =)
first, transpose all terms which does not contain x,, thus we have to transpose the term 3y to the right side of equation, but the sign must be the opposite:
3x + 3y = 9
3x = 9 - 3y *positive 3y becomes negative after transposing
after that, divide the numerical coefficient of x (which is 3) to all terms in the equation to get x:
(3x)/3 = (9)/3 - (3y)/3
x = 3 - y
the steps to solve for y is the same as that of solving for x,, of course, terms that should be transposed to other side of equation must not contain y,, therefore:
3x + 3y = 9 *transpose.
3y = 9 - 3x *then divide by num. coefficient of y (which is 3)
y = 3 - y
so there,, =)