Solve for x, x^2-5x+3
4 answers
Solve for y, y=x^2+4x+16
There is no equation given if you just write down an expression. An equation would have an equals (=) sign. Please provide the full equation so that it can be solved.
I assume that you meant:
solve for x, x^2 + 4x + 16 = 0
using completing the square, ....
x^2 + 4 x + .... = -16 + ....
x^2 + 4 x + 4 = -16 + 4
(x + 2)^2 = -12
x + 2 = ± √-12 = ± 2√3 i
x = -2 ± 2√3 i , which of course is a complex number
solve for x, x^2 + 4x + 16 = 0
using completing the square, ....
x^2 + 4 x + .... = -16 + ....
x^2 + 4 x + 4 = -16 + 4
(x + 2)^2 = -12
x + 2 = ± √-12 = ± 2√3 i
x = -2 ± 2√3 i , which of course is a complex number
Yes, that is correct!
The solutions for x are imaginary since the expression inside the square root is negative.
Well done!
The solutions for x are imaginary since the expression inside the square root is negative.
Well done!