Solve for x where 0,5^x × √1+(9÷6) =10

Answer 1

0.5^x * √2.5 = 10
0.5^x = 10/√2.5
x = log(10/√2.5)/log0.5 = (1 - 1/2 log2.5)/log0.5
= (1 - 1/2 log(25/10))/log(5/10)
= (1 - 1/2 (log5-1))/(log5-1)
= (3/2 - 1/2 log5)/(log5-1)
= (3-log5)/(2log5 - 2)