In this equation, a = 1, b = 2, and c = 1.
Plugging these values into the quadratic formula:
x = (-2 ± √(2^2 - 4*1*1)) / 2*1
x = (-2 ± √(4 - 4)) / 2
x = (-2 ± √0) / 2
x = (-2 ± 0) / 2
x = -2 / 2
x = -1
Therefore, x = -1.
Solve for x using the quadratic formula: x2 + 2x + 1 = 0
x equals negative b plus or minus the square root of b squared minus 4 times a times c, all over 2 times a
x = 2
x = 1
x = 0
x = −1
1 answer