solve for x to determine if the equations has one, none, or infinite solutions 3(x+2)-6=3x

Answer 1

To solve for x, first we will distribute the 3 on the left side of the equation:

3(x+2) - 6 = 3x
3x + 6 - 6 = 3x
3x = 3x

Now we will subtract 3x from both sides of the equation to isolate x:

3x - 3x = 0
0 = 0

Since 0 = 0, this means that the equation has an infinite number of solutions.

Answer 2

solve for x to determine if the equation has one, none, or infinite solutions 4x=3x+5) -15

Answer 3

To solve for x, first we will combine like terms on the right side of the equation:

4x = 3x + 5 - 15
4x = 3x - 10

Now, we will subtract 3x from both sides of the equation to isolate x:

4x - 3x = -10
x = -10

Therefore, the equation has one solution: x = -10.

Answer 4

solve for x to determine if the equation has one, none, or infinite solutions. 5(2x+2)-7x=3x+6

Answer 5

Let's solve for x in the equation:

5(2x+2) - 7x = 3x + 6
Distribute the 5 on the left side:
10x + 10 - 7x = 3x + 6
Combine like terms:
3x + 10 = 3x + 6
Subtract 3x from both sides:
10 = 6

The equation simplifies to 10 = 6, which is not a true statement.
Since the equation has led to a contradiction, there are no solutions for x.