Solve for x:

sin2x + cos^2x = 1
0° < or equal to x < 360°

3 answers

That is an identity, it is true for all values of x.

Try x=-439
o____O
how did you get to that value? can you show me how to solve it algabraeically?
Draw a right triangle with hypotenuse c and sides a and b. Opposite angles are then A, B, C

now sin A = a/c so a = c sin A
cos a = b/c so b = c cos A
right triangle geometry says
a^2 + b^2 =c ^2
so
c^2 sin^2 A + c^2 cos^2 A = c^2
divide both sides by c^2
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