solve for x:
ln(5-2x)=-3
e^[ln(5-2x))=e^-3
5-2x={1/(e^3)}----> Is this part right?
Then I solve for x, right?
1 answer
yes, it's right
ln(5-2x)=-3
e^[ln(5-2x))=e^-3
5-2x={1/(e^3)}----> Is this part right?
Then I solve for x, right?
1 answer
1 answer
1 answer
1 answer
1 answer