Solve for "x" in each equation.

Question

1)xsquared+12x+25= 0
2)xsquared+4x-12= 0
3)xsquared-5x= 50
4)(x+1)squared= 169
5)2xsquared+5x= 12
6)(2x-5)squared= 225
7)x-4/x-3 = x+2/x+1
8)9/2x+1/3= 1/2
9)6/x-1= 3/x
10)2x/2x+2x= 4

Answer 1

You are obviously studying quadratic equations.
With what specific part of this assignment are you having difficulties ?

I will pick two at random

1. x^2 + 12x + 25 = 0
Since the quadratic term has a coefficent of 1 and the middle term is even, completing the square works best
x^2 + 12x = -25
x^2 + 12x + 36 = -25+36
(x+6)^2 = 11
x+6 = ± √11
x = -6 ± √11

for #7 , you must mean
(x-4)/(x-3) = (x+2)/(x+1)
cross-multiply ...
x^2 -3x - 4 = x^2 - x - 6
-2x = -2
x = 1
can you see why my brackets are essential ?

let me know what you get for the others.