Solve for x if the point (x,9) lies on the line 2y-10x+2=0

1 answer

To solve for \( x \) given that the point \( (x, 9) \) lies on the line defined by the equation \( 2y - 10x + 2 = 0 \), we can substitute \( y \) with \( 9 \) in the equation of the line.

Starting with the equation:

\[ 2y - 10x + 2 = 0 \]

Substituting \( y = 9 \):

\[ 2(9) - 10x + 2 = 0 \]

Calculating \( 2(9) \):

\[ 18 - 10x + 2 = 0 \]

Combining the constants:

\[ 20 - 10x = 0 \]

Next, we isolate \( x \):

\[ -10x = -20 \]

Dividing both sides by \(-10\):

\[ x = 2 \]

Thus, the solution for \( x \) is

\[ \boxed{2} \]