solve for x if 1/15(6+x)=1/6(x+3)
6 answers
are the ( ) quantities in the numerator or denominators?
both
both? then you need to write it such as it is. Right now, both are in the denominator.
i do not know how to,but take for instance it was for the numerator alone
the way you typed according to BEDMAS
(1/15)(6+x)=(1/6)(x+3)
multiply both sides by 30
2(6+x) = 5(x+3)
now it is easy, carry on
What Bob meant was:
did you mean,
1/(15(6+x)) =1/(6(x+3)) ?
then we have an entirely different ballgame
(1/15)(6+x)=(1/6)(x+3)
multiply both sides by 30
2(6+x) = 5(x+3)
now it is easy, carry on
What Bob meant was:
did you mean,
1/(15(6+x)) =1/(6(x+3)) ?
then we have an entirely different ballgame
what u did was wat i meant (Reiny) thanks both of u