1) is an example of a quadratic equation in standard form. One could factor, complete the square, or use the quadratic formula. It would be messy, however.
2) Do you have access to a graphing calculator? Are you expected to do this one by hand? What math class are these for?
solve for x:
and could you show me the step on how to do it? thank u!
1) 5.8 = .17x(sqaured)+.95x + 5.68
2) 5.8 = .09x(squared) + .01x (cubed) + 1.1x + 5.64
4 answers
Do you know how to do synthetic or long division of polynomials? The basic idea is that you can find zeroes which would tell you where the x intercepts of the graph are. Trust me this far: Always put the right side of the equals sign in descending order of exponents (cubed first, next comes squared, then comes just plain x which is to the first power anyway, and then the numerical coefficient goes last. The graph will bounce away at even points and cross at odd points. This is all I can remember at this point. Someone else should be able to help you further. I will try to dig through my brain and remember more.
As Brandon stated, the first one can be done by using the quadratic equation formula
for the second, I would multiply each term by 100 and simplify to get
x^3 + 9x^2 + 110x - 16 = 0
and then use a "calculator" like
http://www.1728.com/cubic.htm
enter the coefficients to get one real and two complex roots.
for the second, I would multiply each term by 100 and simplify to get
x^3 + 9x^2 + 110x - 16 = 0
and then use a "calculator" like
http://www.1728.com/cubic.htm
enter the coefficients to get one real and two complex roots.
I followed the link you gave and clicked on their method for solving these that is located on the very bottom of the page. Boy, that is an arduous process! I forgot about clearing decimals and setting one side of the equation to zero. Talk about obvious oversights on my part! In this sense, complex means consisting of both a real portion as well as an imaginary (or "unreal") part. Instead of relying on shortcuts for instant gratification, I would suggest that she actually learn some of the procedures that I listed above.