solve for x

Question

7^x/2=5^1-x

what i have so far is:

(x/2)ln7=(1-x)ln5
im not sure where to go from there

Answer 1

[ln(7) / 2] x = ln(5) - [ln(5)] x

x = ln(5) / {[ln(7) / 2] + ln(5)}

Answer 2

or, after some manipulation,

1/(1+log₅√7)

is that simpler? who can say?