4 (3x + 2) =32
9 answers
To solve the equation \(4(3x + 2) = 32\), follow these steps:
Distribute the 4 on the left side: \[ 12x + 8 = 32 \]
Subtract 8 from both sides to isolate the term with \(x\): \[ 12x = 32 - 8 \] \[ 12x = 24 \]
Divide both sides by 12 to solve for \(x\): \[ x = \frac{24}{12} \] \[ x = 2 \]
Thus, the solution is: \[ \boxed{2} \]
To solve the equation \(-2(3x - 15) = 60\), follow these steps:
Distribute the -2 on the left side: \[ -2 \cdot 3x + -2 \cdot -15 = 60 \] \[ -6x + 30 = 60 \]
Subtract 30 from both sides: \[ -6x = 60 - 30 \] \[ -6x = 30 \]
Divide both sides by -6 to solve for \(x\): \[ x = \frac{30}{-6} \] \[ x = -5 \]
Thus, the solution is: \[ \boxed{-5} \]
To solve the equation \(5(2x - 8) = -30\), follow these steps:
Distribute the 5 on the left side: \[ 5 \cdot 2x - 5 \cdot 8 = -30 \] \[ 10x - 40 = -30 \]
Add 40 to both sides to isolate the term with \(x\): \[ 10x = -30 + 40 \] \[ 10x = 10 \]
Divide both sides by 10 to solve for \(x\): \[ x = \frac{10}{10} \] \[ x = 1 \]
Thus, the solution is: \[ \boxed{1} \]
To solve the equation \(4(3x + 2) + 3 = 35\), follow these steps:
Subtract 3 from both sides to isolate the term with \(x\): \[ 4(3x + 2) = 35 - 3 \] \[ 4(3x + 2) = 32 \]
Divide both sides by 4: \[ 3x + 2 = \frac{32}{4} \] \[ 3x + 2 = 8 \]
Subtract 2 from both sides: \[ 3x = 8 - 2 \] \[ 3x = 6 \]
Divide both sides by 3 to solve for \(x\): \[ x = \frac{6}{3} \] \[ x = 2 \]
Thus, the solution is: \[ \boxed{2} \]
To solve the equation \(-2(3x - 15) - 4 = 56\), follow these steps:
Start by distributing the \(-2\): \[ -2 \cdot 3x + 2 \cdot 15 - 4 = 56 \] \[ -6x + 30 - 4 = 56 \]
Combine like terms on the left side: \[ -6x + 26 = 56 \]
Subtract 26 from both sides to isolate the term with \(x\): \[ -6x = 56 - 26 \] \[ -6x = 30 \]
Divide both sides by \(-6\) to solve for \(x\): \[ x = \frac{30}{-6} \] \[ x = -5 \]
Thus, the solution is: \[ \boxed{-5} \]
