To solve for x, we need to isolate x on one side of the equation.
Starting with the equation 4(3x + 2) = 32, we can distribute 4 to the terms inside the parentheses:
12x + 8 = 32
Next, we can solve for x by subtracting 8 from both sides of the equation:
12x = 24
Lastly, we can divide both sides of the equation by 12 to solve for x:
x = 2
Therefore, x = 2.
Solve for x . 4(3x+2)=32 (1 point)x=
9 answers
Solve for x . −2(3x−15)=60 (1 point)x=
To solve for x, we need to isolate x on one side of the equation.
Starting with the equation -2(3x - 15) = 60, we can distribute -2 to the terms inside the parentheses:
-6x + 30 = 60
Next, we can solve for x by subtracting 30 from both sides of the equation:
-6x = 30
Lastly, we can divide both sides of the equation by -6 to solve for x:
x = -5
Therefore, x = -5.
Starting with the equation -2(3x - 15) = 60, we can distribute -2 to the terms inside the parentheses:
-6x + 30 = 60
Next, we can solve for x by subtracting 30 from both sides of the equation:
-6x = 30
Lastly, we can divide both sides of the equation by -6 to solve for x:
x = -5
Therefore, x = -5.
Solve for x . 5(2x−8)=−30 (1 point)x=
To solve for x, we need to isolate x on one side of the equation.
Starting with the equation 5(2x - 8) = -30, we can distribute 5 to the terms inside the parentheses:
10x - 40 = -30
Next, we can solve for x by adding 40 to both sides of the equation:
10x = 10
Lastly, we can divide both sides of the equation by 10 to solve for x:
x = 1
Therefore, x = 1.
Starting with the equation 5(2x - 8) = -30, we can distribute 5 to the terms inside the parentheses:
10x - 40 = -30
Next, we can solve for x by adding 40 to both sides of the equation:
10x = 10
Lastly, we can divide both sides of the equation by 10 to solve for x:
x = 1
Therefore, x = 1.
Solve for x : 4(3x+2)+3=35 .(1 point)x=
To solve for x, we need to isolate x on one side of the equation.
Starting with the equation 4(3x + 2) + 3 = 35, we can first distribute 4 to the terms inside the parentheses:
12x + 8 + 3 = 35
Then we combine like terms:
12x + 11 = 35
Next, we can isolate x by subtracting 11 from both sides of the equation:
12x = 35 - 11
12x = 24
Lastly, we can solve for x by dividing both sides of the equation by 12:
x = 24 / 12
x = 2
Therefore, x = 2.
Starting with the equation 4(3x + 2) + 3 = 35, we can first distribute 4 to the terms inside the parentheses:
12x + 8 + 3 = 35
Then we combine like terms:
12x + 11 = 35
Next, we can isolate x by subtracting 11 from both sides of the equation:
12x = 35 - 11
12x = 24
Lastly, we can solve for x by dividing both sides of the equation by 12:
x = 24 / 12
x = 2
Therefore, x = 2.
Solve for x : −2(3x−15)−4=56 .(1 point)x=
To solve for x, we need to isolate x on one side of the equation.
Starting with the equation -2(3x - 15) - 4 = 56, we can first distribute -2 to the terms inside the parentheses:
-6x + 30 - 4 = 56
Then we combine like terms:
-6x + 26 = 56
Next, we can isolate x by subtracting 26 from both sides of the equation:
-6x = 56 - 26
-6x = 30
Lastly, we can solve for x by dividing both sides of the equation by -6:
x = 30 / -6
x = -5
Therefore, x = -5.
Starting with the equation -2(3x - 15) - 4 = 56, we can first distribute -2 to the terms inside the parentheses:
-6x + 30 - 4 = 56
Then we combine like terms:
-6x + 26 = 56
Next, we can isolate x by subtracting 26 from both sides of the equation:
-6x = 56 - 26
-6x = 30
Lastly, we can solve for x by dividing both sides of the equation by -6:
x = 30 / -6
x = -5
Therefore, x = -5.