Solve for X: 3x^2 +15X + 18 = 0
Responses
5, 6
2, 3
15, 18
-2, -3
3 answers
-2, -3
can you explain.
To solve for x in the quadratic equation 3x^2 +15x + 18 = 0, we can use the quadratic formula:
x = (-b ± √(b²-4ac)) / 2a
In this case, a = 3, b = 15, and c = 18. Plugging those values into the formula, we get:
x = (-15 ± √(15² - 4(3)(18))) / 2(3)
x = (-15 ± √(225 - 216)) / 6
x = (-15 ± √9) / 6
x = (-15 ± 3) / 6
This gives us two solutions:
x = (-15 + 3) / 6 = -12 / 6 = -2
x = (-15 - 3) / 6 = -18 / 6 = -3
Therefore, the solutions are x = -2 and x = -3.
x = (-b ± √(b²-4ac)) / 2a
In this case, a = 3, b = 15, and c = 18. Plugging those values into the formula, we get:
x = (-15 ± √(15² - 4(3)(18))) / 2(3)
x = (-15 ± √(225 - 216)) / 6
x = (-15 ± √9) / 6
x = (-15 ± 3) / 6
This gives us two solutions:
x = (-15 + 3) / 6 = -12 / 6 = -2
x = (-15 - 3) / 6 = -18 / 6 = -3
Therefore, the solutions are x = -2 and x = -3.