To solve for X, we first need to rewrite the equation in the form of a quadratic equation:
10x^2 + 13x - 3 = 0
Now, we can use the quadratic formula to find the values of X:
X = [-b ± √(b^2 - 4ac)] / 2a
Where a = 10, b = 13, and c = -3
Plugging in the values into the formula:
X = [-13 ± √(13^2 - 4(10)(-3))] / 2(10)
X = [-13 ± √(169 + 120)] / 20
X = [-13 ± √289] / 20
X = [-13 ± 17] / 20
This gives us two possible solutions for X:
X = (4) / 20 = 1/5 = 0.2
X = (-30) / 20 = -3/2 = -1.5
Therefore, X can be 0.2 or -1.5.
Solve for X:
3= 10x^2 + 13x
Responses
2, 5
−
1
5
32 , −15
3
2
-3, -1
−32 , 15
1 answer