18x^3 + 15x^2 + 18x = 0
3x(6x^2 + 5x + 6) = 0
so x = 0 or x = ...... (use the quadratic formula, I see imaginary roots coming up here )
solve for x: 2xcubed+18x=-15xsquared
2 answers
just noticed it was
2x^3 + 15x^2 + 18x = 0
x(2x^2 + 15x + 18) = 0
x(2x+3)(x+6) = 0
x = 0 or x = -3/2 or x = -6
2x^3 + 15x^2 + 18x = 0
x(2x^2 + 15x + 18) = 0
x(2x+3)(x+6) = 0
x = 0 or x = -3/2 or x = -6