Solve for x.

Question

2x2 + 8x – 10 = 0
(1 point)

a. x = –5, 2

b. x = 5, –2

c. x = –5, 1

d. x = 5, –1

Answer 1

Using the quadratic formula, we can solve for x:

x = (-b ± √(b^2 - 4ac))/(2a)

In this case, a = 2, b = 8, and c = -10. Substituting these values into the quadratic formula, we get:

x = (-8 ± √(8^2 - 4(2)(-10)))/(2(2))
x = (-8 ± √(64 + 80))/4
x = (-8 ± √(144))/4
x = (-8 ± 12)/4

This gives us two solutions:

x = (-8 + 12)/4 = 4/4 = 1

x = (-8 - 12)/4 = -20/4 = -5

Therefore, the correct answer is: c. x = –5, 1