Solve for the width in the formula for the area of a rectangle.

Use the rewritten formula to find the width of a rectangle with an area of 42 square inches and a length of 16.8 inches.

9 answers

The area \( A \) of a rectangle can be calculated using the formula:

\[ A = \text{length} \times \text{width} \]

To solve for the width, we can rewrite the formula as follows:

\[ \text{width} = \frac{A}{\text{length}} \]

Now, we can use this rewritten formula to find the width of a rectangle with an area of \( 42 \) square inches and a length of \( 16.8 \) inches.

Substituting the values into the formula:

\[ \text{width} = \frac{42}{16.8} \]

Now, we perform the division:

\[ \text{width} = 2.5 \]

Thus, the width of the rectangle is \( 2.5 \) inches.

Solve for the width in the formula for the area of a rectangle.

W=A-I
W=AI
W=I/A
W=A/I

To solve for the width \( W \) in the formula for the area of a rectangle, we start with the standard area formula:

\[ A = \text{length} \times \text{width} \]

Since you have provided several equations, let's clarify each of them in terms of an area \( A \), length \( L \), and width \( W \):

  1. W = A - I: This doesn't relate to the area calculation.
  2. W = AI: This doesn't relate to the area calculation.
  3. W = I/A: This doesn't relate to the area calculation and measures the inverse relationship.
  4. W = A/I: This is not standard for width as it suggests taking the area and dividing by some measure \( I \).

The correct rearrangement of the area formula for width would be:

\[ W = \frac{A}{L} \]

If you want to use this to find the width given an area \( A \) and length \( L \), you can substitute those values as follows:

If \( A = 42 \) square inches and \( L = 16.8 \) inches, then:

\[ W = \frac{42}{16.8} \]

Calculating that:

\[ W = 2.5 \text{ inches} \]

So, the correct formula is \( W = \frac{A}{L} \), and the width of the rectangle is \( 2.5 \) inches.

The surface area of a cone is given by the formula%0D%0AS = πl + πr2. Solve the formula for l.%0D%0A%0D%0Al = S – r2%0D%0Al = S + r2%0D%0Al = – r2%0D%0Al = + r2 okay if you do solve this explain how you do it NO NUMBERS WITH WORDS

The image is a diagram of a cone. It labels the slant height of the cone as ( l ) and the radius of the base of the cone as ( r ). An arrow pointing to the side of the cone indicates the slant height.

To solve the formula for the surface area of a cone, we start with the given formula:

\[ S = \pi l + \pi r^2 \]

Here, \( S \) represents the surface area, \( l \) is the slant height, \( r \) is the radius of the base, and \( \pi \) is a constant.

Steps to Solve for \( l \):

  1. Isolate the term involving \( l \):

    • The first step is to rearrange the equation to isolate the term with \( l \). To do this, we want to move \( \pi r^2 \) to the other side of the equation. This can be done by subtracting \( \pi r^2 \) from both sides of the equation: \[ S - \pi r^2 = \pi l \]
  2. Solve for \( l \):

    • Now that we have isolated \( \pi l \), the next step is to solve for \( l \) by dividing both sides of the equation by \( \pi \): \[ l = \frac{S - \pi r^2}{\pi} \]

This gives us the expression for \( l \) in terms of \( S \) and \( r \).

Summary of Restructured Formula:

After solving for \( l \), we have:

\[ l = \frac{S - \pi r^2}{\pi} \]

This expression shows how the slant height \( l \) of the cone can be determined using the surface area \( S \) and the radius \( r \) of the base.

Important Note: During this process, the operations included isolating terms and dividing through by constants, which is standard practice in algebra for solving equations. The original solution attempt contained multiple incorrect statements which are not valid transformations of the equation.

The formula for the slant height of a cone is t equals StartFraction S minus pi r squared Over pi EndFraction. , where S is surface area of the cone. Use the formula to find the slant height, l, of a cone with a surface area of 500π ft2 and a radius of 15 ft.

l =
ft

To find the slant height \( l \) of a cone using the formula

\[ l = \frac{S - \pi r^2}{\pi} \]

we will substitute the values for \( S \) (surface area) and \( r \) (radius) into the formula.

Given:

  • \( S = 500\pi , \text{ft}^2 \)
  • \( r = 15 , \text{ft} \)

Step 1: Calculate \( \pi r^2 \)

First, we need to calculate \( \pi r^2 \):

\[ \pi r^2 = \pi (15)^2 = \pi (225) = 225\pi \]

Step 2: Substitute the Values into the Formula

Now substitute \( S \) and \( \pi r^2 \) into the formula for \( l \):

\[ l = \frac{500\pi - 225\pi}{\pi} \]

Step 3: Simplify the Expression

Combine the terms in the numerator:

\[ l = \frac{(500 - 225)\pi}{\pi} \]

This simplifies to:

\[ l = \frac{275\pi}{\pi} \]

Step 4: Further Simplification

The \( \pi \) in the numerator and denominator cancels out:

\[ l = 275 \]

Thus, the slant height \( l \) of the cone is

\[ l = 275 , \text{ft} \]

THe answer for that other quedstion btw is l = S/pi- – r2

Thank you for your input! Let's clarify the formula step for solving for the slant height \( l \) from the surface area \( S \) of the cone, specifically focusing on the correct formulation.

The formula for the surface area of a cone is:

\[ S = \pi l + \pi r^2 \]

To isolate \( l \):

  1. Subtract \( \pi r^2 \) from both sides: \[ S - \pi r^2 = \pi l \]

  2. Divide both sides by \( \pi \): \[ l = \frac{S - \pi r^2}{\pi} \]

This can be rewritten as:

\[ l = \frac{S}{\pi} - r^2 \]

However, there appears to be a slight misunderstanding in interpretation here. The most common expression remains as:

\[ l = \frac{S - \pi r^2}{\pi} \]

So let's double-check your specific expression:

If you have:

\[ l = \frac{S}{\pi} - r^2 \]

This would be valid in the context where

  • \( S \) is the total surface area,
  • \( r^2 \) is the term that needs to be separately identified (though it typically does not subtract in that way in the original formula).

Conclusion

The correct derived formula remains:

\[ l = \frac{S - \pi r^2}{\pi} \]

If you would like me to elaborate more or clarify further, please let me know! Thank you for your diligence.