To solve the equation \((n + 1)(n - 8) = 0\), we can set each factor equal to zero:
- \(n + 1 = 0\)
- \(n - 8 = 0\)
Now, let's solve each equation:
-
For \(n + 1 = 0\): \[ n = -1 \]
-
For \(n - 8 = 0\): \[ n = 8 \]
So, the solutions for \(n\) are: \[ n = -1 \quad \text{or} \quad n = 8 \]