Solve for
\[n\].
\[\left(7^2\right)^{4}=n^8\]
1 answer
We have \[\left(7^2\right)^4 = 7^{2\cdot 4} = 7^8,\]so we must have $n^8 = 7^8$. Taking eighth roots, we find $n = \boxed{7}$.
\[n\].
\[\left(7^2\right)^{4}=n^8\]
1 answer