To solve the equation \( j^2 - 67 = -3 \), we can start by isolating \( j^2 \):
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Add 67 to both sides: \[ j^2 - 67 + 67 = -3 + 67 \] \[ j^2 = 64 \]
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Now, take the square root of both sides: \[ j = \pm \sqrt{64} \] \[ j = \pm 8 \]
So, the solutions are: \[ j = 8 \quad \text{or} \quad j = -8 \]