To solve the equation \( d^2 - 16 = 0 \), we can start by adding 16 to both sides of the equation:
\[ d^2 = 16 \]
Next, we take the square root of both sides. Remember to consider both the positive and negative roots:
\[ d = \pm \sqrt{16} \]
Calculating the square root gives us:
\[ d = \pm 4 \]
Thus, the solutions for \( d \) are:
\[ d = 4 \quad \text{and} \quad d = -4 \]
So, the final answers are:
\[ d = 4 \quad \text{or} \quad d = -4 \]
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