solve for all values in [0,2pie)

Question

2sin^2x-1=0

Answer 1

2sin^2x-1=0
sin^2 x = 1/2
sinx = ±1/√2

I know sin 45° = 1/√2 or sin π/4 = 1/√2

because of the ± , our angle could be in any of the 4 quadrants
so x = π/4 , 3π/4, 5π/4 , 7π/4