Solve for all real values of y: |3y+7|=|2y-1|.

Answer 1

this can be reduced to two cases, actually 4, but 2 are duplicates
+ -- +
+ -- -
- -- +
- -- -

3y+7 = 2y-1 or 3y+7 = -2y + 1
y = -8 or 5y = -6

y = -8 or y = -6/5