Solve for all real values of x
x² + 10 = 0
-10. -10
x² = -10
√x² = ± √-10
x = ± √(-10)
Since the square root of a negative number involves imaginary numbers, we can express √(-10) as:
x = ± i√10
Solutions: x = i√10, x = -i√10
There are no real solutions for this equation.