Solve exactly for
x: sin^3 x + sin x cos^2 x = cos x
If 0 degrees <= x <= 180 degrees
x = ? degrees?
Would i factor out sin^3 x from the left side and the right. and try to solve from there?
2 answers
never mind disregard this. I found the answer to be 45 degrees
sin^3 x + sinx cos^2 x = cosx
sinx(sin^2 x + cos^2 x) = cosx
sinx (1) = cosx
sinx/cosx = 1
tanx = 1
x = 45° or x = 225°
but you wanted to be between 0 and 180
so x = 45°
sinx(sin^2 x + cos^2 x) = cosx
sinx (1) = cosx
sinx/cosx = 1
tanx = 1
x = 45° or x = 225°
but you wanted to be between 0 and 180
so x = 45°
1 answer