Solve exactly for

x: sin^3 x + sin x cos^2 x = cos x

If 0 degrees <= x <= 180 degrees

x = ? degrees?

Would i factor out sin^3 x from the left side and the right. and try to solve from there?

2 answers

never mind disregard this. I found the answer to be 45 degrees
sin^3 x + sinx cos^2 x = cosx
sinx(sin^2 x + cos^2 x) = cosx
sinx (1) = cosx
sinx/cosx = 1
tanx = 1
x = 45° or x = 225°
but you wanted to be between 0 and 180

so x = 45°
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