Solve each system of equations by substitution:

Question

x^2 - y +2 = 0
4x = 14 -y

y + 2x = x^2 - 6
x + y - 3 = 2x^2

Answer 1

x^2 - y +2 = 0
4x = 14 -y
y=14-4x

x^2-(14-4x) +2=0
x^2+4x-12=0
(x+6)(x-2)=0
x=6; x=2, y=-10;6