x+y=6
-(x-y=4)
________
2y=2
- - <divide both sides by 2, to get y
2 2
______
y=1
Set x+1=6
x=6-1=5
____Need to check
y=2 and x=5 if its true
--------
5+2=7 not 4
5-2=3 not 4
{No solution}
Solve each system graphically. If a system has an infinite number of solutions, use set builder notation to write the solution set. If a system has no solution,
state this. x + y = 6
x - y = 4
I'm lost, Please Help!! Thank you
2 answers
I meant to say at the end that
if:
x=5 and y=2
and you plug them into the 2 equations that answer are different.
x+y=6
(5)+(2)=7 , not true
x-y=4
(5)-(2)=3
Hope this helps
if:
x=5 and y=2
and you plug them into the 2 equations that answer are different.
x+y=6
(5)+(2)=7 , not true
x-y=4
(5)-(2)=3
Hope this helps