To solve this system by substitution, we can substitute the value of y from the first equation into the second equation.
In the first equation, we are given that y = 5.
Substituting y = 5 into the second equation, we have:
-3x + 4(5) = 8
Simplifying this equation, we get:
-3x + 20 = 8
To isolate x, we can subtract 20 from both sides:
-3x = 8 - 20
-3x = -12
Dividing both sides by -3, we find:
x = -12 / -3
x = 4
Therefore, the solution to the system is x = 4 and y = 5.
Solve each system by substitution
Y = 5
-3x + 4y = 8
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