Solve each system by substitution

Question

X = 5
X + y = 12

Answer 1

To solve the system by substitution, we start with the first equation:

X = 5

Next, we substitute this value of X into the second equation:

5 + y = 12

Now, we can solve for y by subtracting 5 from both sides:

y = 12 - 5
y = 7

So the solution to the system is X = 5 and y = 7.

Answer 2

Solve each system by substitution
Y = 5
-3x + 4y = 8

Answer 3

To solve the system by substitution, we start with the first equation:

Y = 5

Next, we substitute this value of Y into the second equation:

-3x + 4(5) = 8

Simplifying, we have:

-3x + 20 = 8

Now, we can solve for x by subtracting 20 from both sides:

-3x = 8 - 20
-3x = -12

Dividing by -3, we get:

x = -12 / -3
x = 4

So the solution to the system is x = 4 and Y = 5.

Answer 4

Solve each system by substitution
y=-3x
4x - 2y = -20

Answer 5

To solve the system by substitution, we start with the first equation:

y = -3x

Next, we substitute this value of y into the second equation:

4x - 2(-3x) = -20

Simplifying, we have:

4x + 6x = -20

Combining like terms, we get:

10x = -20

Dividing by 10, we have:

x = -20 / 10
x = -2

Now, we substitute this value of x back into the first equation to solve for y:

y = -3(-2)

Simplifying, we have:

y = 6

So the solution to the system is x = -2 and y = 6.

Answer 6

Solve each system by substitution
Y = -3x + 4
Y = 4x - 10

Answer 7

To solve the system by substitution, we set the two equations equal to each other:

-3x + 4 = 4x - 10

Next, we group the x terms on one side and the constant terms on the other side:

4 + 10 = 4x + 3x

14 = 7x

Now, we solve for x by dividing both sides by 7:

x = 14 / 7
x = 2

Now that we have the value of x, we substitute it back into one of the original equations to solve for y. Let's use the first equation:

y = -3(2) + 4
y = -6 + 4
y = -2

So the solution to the system is x = 2 and y = -2.