Elimination.
6x + 8y = -34
6x + 9y = -39
Subtracting the first from the second, gives you y = -5
Use that in one of the original equations to find x.
Solve each of the following systems, if possible. Indicate whether the system has a unique solution, infinitely many solutions, or no solution.
3x+4y=-17
2x+3y=-13
Please help ASAP I'm having a hard time doing this problem. I can either use substitution or elimination in this problem.
2 answers
You should use elimination.
Firstly, multiply both equations so that the coefficients of the "x" variable are the same:
2(3x+4y=-17) --> 6x+8y=-34
3(2x+3y=-13) --> 6x+9y=-39
Now, do the elimination:
6x+8y=-34
- 6x+9y=-39
-------------------
-y=5 --> y=-5
Now that you found "y", you can just substitute that value in one of the two equations. I will use the original first equation:
3x+4(-5)=-17
3x-20=-17
3x=3 --> x=1
So, we come to the conclusion that x=1, and y=-5.
Firstly, multiply both equations so that the coefficients of the "x" variable are the same:
2(3x+4y=-17) --> 6x+8y=-34
3(2x+3y=-13) --> 6x+9y=-39
Now, do the elimination:
6x+8y=-34
- 6x+9y=-39
-------------------
-y=5 --> y=-5
Now that you found "y", you can just substitute that value in one of the two equations. I will use the original first equation:
3x+4(-5)=-17
3x-20=-17
3x=3 --> x=1
So, we come to the conclusion that x=1, and y=-5.
1 answer