solve each following system by substitution 4x-12y=5 -x+3y=-1
3 answers
I think something is wrong with your problem...
I assume the two equations are as follows:
4x-12y=5 and
-x+3y=-1
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To solve by substitution, take either equation, I'll take #2, and solve for either x or y. I'll solve for x, so
-x + 3Y = -1
-x = -1-3y
multiply through by -1 to give
x=1+3y. Now that value of x goes into x in equation #1.
#1 is
4x-12y=5
substitute the value of x you have from the work bove.
4(1+3y)-12y=5 and solve for y.
This is the way to eliminate one of the variables. Post your work if you get stuck.
4x-12y=5 and
-x+3y=-1
==============
To solve by substitution, take either equation, I'll take #2, and solve for either x or y. I'll solve for x, so
-x + 3Y = -1
-x = -1-3y
multiply through by -1 to give
x=1+3y. Now that value of x goes into x in equation #1.
#1 is
4x-12y=5
substitute the value of x you have from the work bove.
4(1+3y)-12y=5 and solve for y.
This is the way to eliminate one of the variables. Post your work if you get stuck.
Thanks