You need to use parentheses to clarify what the numerators and denominators are.
For example, do you mean
(y+7)/(2y-6) +1, or
y + 7/(2y-6) +1 ?
Solve each equation. Watch for extraneous solutions
5/y-3 = y+7/2y-6 +1
3 answers
5 is numerator/ y-3 is denominator
y + 7/(2y-6) +1
y +7 is numerator, 2-y is denominator the whole thing +1
y + 7/(2y-6) +1
y +7 is numerator, 2-y is denominator the whole thing +1
If Sandra's comments are correcta about "Joe's" question,
5/(y-3) = (y+7)/[2(y-3)] +1
10/[2(y-3)]- (y+7)/[2(y-3)] = 1
(10 -y -7)/(y-3) = 2
3-y = 2(y-3) = 2y -6
3y = 9
y = 3
However, the original equation is undefined when y = 3
5/(y-3) = (y+7)/[2(y-3)] +1
10/[2(y-3)]- (y+7)/[2(y-3)] = 1
(10 -y -7)/(y-3) = 2
3-y = 2(y-3) = 2y -6
3y = 9
y = 3
However, the original equation is undefined when y = 3
1 answer