Solve each equation for 0<_ 0<_ 2pi(3.14)

A) 2cos^20 - sin0 -1=0
My answers: sin0= -1/2 or sin0=1 so 0 = 7pi/6, 11pi/6 and pi/2

But the back of the book says: pi/6, 5pi/6 and 3pi/2

1 answer

2-2sin^2-sin-1=0
2sin^2+sin-1 = 0
(2sin-1)(sin+1) = 0
sin = 1/2 or -1
sin = 1/2 at pi/6 and 5pi/6
sin = -1 at 3pi/2

Better check your factoring.
Your angles are correct for the values you obtained, but those values had the wrong signs, and hence, the wrong sines :-)
Similar Questions
  1. What is the first step in solving the linear system{2x − 3y = 11 {−x + 5y = −9 by the substitution method in the most
    1. answers icon 2 answers
  2. What is the first step in solving the linear system{2x−3y=11 {−x+5y=−9 by the substitution method in the most efficient
    1. answers icon 4 answers
  3. Solving Multi-Step Equation Quiz1.Solve the Equation x5=−2 A. -35 B. -10 C.3 2. Solve the equation. x5+1=−7 A. -13 B. -40 C.
    1. answers icon 1 answer
  4. You need to solve this equation for x: ax-7=26Which equation would be best first step you could make to solve the equation? (1
    1. answers icon 1 answer
more similar questions