Solve:

du/dt = (sin t) / (u^2 + 1)

So far I got:

arctan u = -ln |csc t + cot t| + C

I'm not sure where to go from there. Thank you so much for the help!

1 answer

Separate the variables:

(u^2 + 1) du = sin t dt

Now integrate

2/3 u^3 + u = -cos t
Similar Questions
    1. answers icon 1 answer
  1. arctan(tan(2pi/3)thanks. arctan(tan(2pi/3) = -pi/3 since arctan and tan are inverse operations, the solution would be 2pi/3 the
    1. answers icon 0 answers
  2. Now we prove Machin's formula using the tangent addition formula:tan(A+B)= tanA+tanB/1-tanAtanB. If A= arctan(120/119) and B=
    1. answers icon 2 answers
  3. Arrange these in order from least to greatest:arctan(-sqrt3), arctan 0, arctan(1/2) So far I got the first two values,
    1. answers icon 2 answers
more similar questions