Asked by don

Solve cosxtanx + sqroot3cosx - sqroot3/2tanx - 3/2 = 0
interval 0 to 2 pi
exact answers and formula for the general solution as well as the specific solutions.

Sorry Steve, missed it last night.

Answers

Answered by Steve
If I'm reading it right, we have

cos tan + √3 cos - √3/2 tan - 3/2 = 0

rearrange terms a bit to get

tan(cos - √3/2) + √3(cos - √3/2) = 0
(tan + √3)(cos - √3/2) = 0

tan x = -√3 --> x = 2pi/3 or 4pi/3
x = (2k+1)*pi +/- pi/3

cos x = √3/2 --> x = pi/6 or 11pi/6
x = k*2pi +/- pi/6
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