If I'm reading it right, we have
cos tan + √3 cos - √3/2 tan - 3/2 = 0
rearrange terms a bit to get
tan(cos - √3/2) + √3(cos - √3/2) = 0
(tan + √3)(cos - √3/2) = 0
tan x = -√3 --> x = 2pi/3 or 4pi/3
x = (2k+1)*pi +/- pi/3
cos x = √3/2 --> x = pi/6 or 11pi/6
x = k*2pi +/- pi/6
Solve cosxtanx + sqroot3cosx - sqroot3/2tanx - 3/2 = 0
interval 0 to 2 pi
exact answers and formula for the general solution as well as the specific solutions.
Sorry Steve, missed it last night.
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