we know that
cos π/6 = √3/2
and
cos(π±x) = -cos(x)
cos(2π±x) = cos(x)
solve cosx= (squareroot3)/ 2 where 0 <(with a line underneath) x <(with a line underneath) 2 pie
a) how many solutions are possible?
b) in which quadrants would you find the solutions?
c) determine the related angle for the equation.
d) determine all the solutions for the equation
2 answers
Steve is correct with the reasoning. Anyways, the answers are:
a) 2
b) I and IV
c) π/6 radians (30 degrees) and -π/6 (330 degrees)
d) 2nπ ± π/6 radians (n=any integer)
a) 2
b) I and IV
c) π/6 radians (30 degrees) and -π/6 (330 degrees)
d) 2nπ ± π/6 radians (n=any integer)
0 answers