Solve cos(5x-10°)=sin(20-3x) pls help me and pls show the working

Answer 1

Recall that
sin ( 90 - A ) = cos A
cos ( 90 - A ) = sin A

cos(5x-10°)=sin(20-3x)
If A=20-3x
Cos(5x-10)=cos(90-(20-3x)

Cos(5x-10)=cos (90-20+3x)

Cos(5x-10)=cos(70+3x)
Compare

5x-10=70+3x

2x=80

X=40°