{ (6x-14) + (x^2-5x) ] /[2(x-5) ] =16/[2(x-5)]
x^2 + x - 14 = 16
x^2 + x - 30 = 0
(x-5)(x+6) = 0
x = 5 or -6
Solve. Check your answer.
1. ((3x-7)/(x-5)) + ((x)/(2)) = ((8)/(x-5))
A: ?
3 answers
Oh delete the x = 5, denominator of original is 0
Not in domain
Not in domain
Nasty !!! at 2:30 m