Thank you for clarifying your unconventional notation.
1) sqrt(3x +7) = x-1
3x + 7 = x^2 -2x + 1
x^2 -5x -6 = 0
(x-6)(x+1) = 0
x = 6 or -1
2. 3*sqrt(2x-3) = 9
sqrt(2x -3) = 3
2x -3 = 9
x = 6
Solve. Check for extraneous solutions.
1) (/3x+7) = x-1
2) (3/2x)-3=9
Note: (/3x+7) is the square root of 3x plus 7 and (3/2x)-3=9 is 3 times the square root of 2x - 3 equals 9.
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