Solve by using the quadratic formula

x^2=-7x+12

First, put all the terms on one side.

x^2=-7x+12

x^2 + 7x -12 = 0

If the original sign for the 12 were negative, this would lead you to:

x^2 + 7x + 12 = 0

This could factor into:

(x+3)(x+4) = 0

However, as you have formula posted, it cannot be factored.

I hope this helps. Thanks for asking.

x=(-7/2)+(sq97)/(2),(-7/2)-(sq97)/(2)

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