To solve the equation \( 4m^2 - 5m - 6 = 0 \) by factoring, we need to find factors of the quadratic expression.
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Start by identifying \( a \), \( b \), and \( c \) in the quadratic equation \( ax^2 + bx + c \):
- \( a = 4 \)
- \( b = -5 \)
- \( c = -6 \)
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To factor the quadratic, we look for two numbers that multiply to \( ac \) (which is \( 4 \times -6 = -24 \)) and add up to \( b \) (which is \(-5\)).
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The two numbers that satisfy these conditions are \( -8 \) and \( 3 \):
- \( -8 \times 3 = -24 \)
- \( -8 + 3 = -5 \)
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Rewrite the middle term using these two numbers: \[ 4m^2 - 8m + 3m - 6 = 0 \]
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Factor by grouping: \[ (4m^2 - 8m) + (3m - 6) = 0 \] \[ 4m(m - 2) + 3(m - 2) = 0 \]
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Now factor out the common factor \( (m - 2) \): \[ (m - 2)(4m + 3) = 0 \]
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Set each factor equal to zero: \[ m - 2 = 0 \quad \text{or} \quad 4m + 3 = 0 \]
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Solve for \( m \):
- From \( m - 2 = 0 \): \[ m = 2 \]
- From \( 4m + 3 = 0 \): \[ 4m = -3 \quad \Rightarrow \quad m = -\frac{3}{4} \]
Thus, the solutions are: \[ m = 2, -\frac{3}{4} \]
In comma-separated form, the final answer is: \[ \boxed{2, -\frac{3}{4}} \]