What are the factors of 12? (6 & 2, 3 & 4)
Which combination of those will add to -1?
(x - 4)(x + 3) = 0
x = 4 or -3
Solve by factoring:
1.) x^2 - x - 12 = 0
3 answers
First in these type of problems if there is a variable that is squared i always start by putting those in first
1) (x ) (x )
then i decide if im going to need a - or + and in this case because we want to make it - we have to put one of each
2)(x- )(x+ )
then i just start by plugging in numbers and the correct answer i found was..
(x-4)(x+3)
if you need help on others just post em:)
1) (x ) (x )
then i decide if im going to need a - or + and in this case because we want to make it - we have to put one of each
2)(x- )(x+ )
then i just start by plugging in numbers and the correct answer i found was..
(x-4)(x+3)
if you need help on others just post em:)
of yes. sorry i almost forget
whenever solving for x
take the problem
(x-4)(x+3)
and make each their own equation
1) (x-4)=0
2)(x+3)=0
then add the 4 and the subtract the three and you get
x=4,-3
whenever solving for x
take the problem
(x-4)(x+3)
and make each their own equation
1) (x-4)=0
2)(x+3)=0
then add the 4 and the subtract the three and you get
x=4,-3