Solve by completing the square: A rectangular patio has a length of (x + 6) m, a width of (x + 8) m, and a total area of 400 m2. Find the dimensions to the nearest tenth.
Please help me with this math problem. Thanks so much.
4 answers
m^2*
(x+6)(x+8) = 400
x^2+14x+48 = 400
x^2+14x+49 = 401
(x+7)^2 = 401
x+7 = ±√401
x = -7±√401
we want a positive value for x+6, so x=-7+√401 ≈13.025
So the dimensions are 19.025 by 21.025
Note that (x+6)(x+8) = (x+7-1)(x+7+1) = (x+7)^2 - 1^2 as seen above
x^2+14x+48 = 400
x^2+14x+49 = 401
(x+7)^2 = 401
x+7 = ±√401
x = -7±√401
we want a positive value for x+6, so x=-7+√401 ≈13.025
So the dimensions are 19.025 by 21.025
Note that (x+6)(x+8) = (x+7-1)(x+7+1) = (x+7)^2 - 1^2 as seen above
I need help too
2021 and they’re still giving out the same pieces of homework
0 answers