Solve by completing the square 3x(sqaured) - 8x - 6 = 0.

Question

Is it 4 - the square root of 34 / 3 and 4 + the square root of 34 / 3?

Answer 1

3x^2 - 8x - 6 = 0
x^2 - 8/3 x = 2
x^2 - 8/3 x + (4/3)^2 = 2 + (4/3)^2
(x - 4/3)^2 = 2 + 16/9 = 34/9
x - 4/3 = ±√34/3
x = 4/3 ±√34/3
x = (4±√34)/3

you are correct

Answer 2

Thank you!