solve by completing square method 16x^2-24x-13=0

Answer 1

16x^2-24x-13=0
16(x^2 - 3/2 x) = 13
16(x^2 - 3/2 x + (3/4)^2 = 13+16(3/4)^2
16(x-3/4)^2 = 22
(x-3/4)^2 = 11/8
x = 3/4 ±√(11/8)
or, x = (3±√22)/4

or, eschewing fractions,

16x^2-24x-13 = 0
16x^2-24x+9 = 13+9
(4x-3)^2 = 22
...