To solve the equation ax - 12 = 9, we can isolate x by performing inverse operations.
First, we add 12 to both sides of the equation to get:
ax - 12 + 12 = 9 + 12
This simplifies to:
ax = 21
Now, we divide both sides of the equation by a to solve for x:
(ax) / a = 21 / a
The a on the left side cancels out, leaving us with:
x = 21 / a
Hence, the solution is x = 21 / a.
Solve ax−12=9
3 answers
The area of a rectangle is calculated with the formula A=lw. If the area of a rectangle is 52.5 m2 and the width is 5 m, what is the length? Explain the solution to the real-world problem.
To find the length of the rectangle, we can use the formula for the area of a rectangle, which is A = lw, where A represents the area, l represents the length, and w represents the width.
In this problem, we are given that the area is 52.5 m² and the width is 5 m. We need to determine the length.
We can rearrange the formula to solve for length by dividing both sides by the width:
l = A / w
Substituting the given values:
l = 52.5 m² / 5 m
l = 10.5 m
Therefore, the length of the rectangle is 10.5 m.
The solution to the real-world problem is that if the area of a rectangle is known to be 52.5 m² and the width is 5 m, the length is 10.5 m. This means that if you were to multiply the length by the width, you would get an area of 52.5 m². The length and width together determine the size of the rectangle.
In this problem, we are given that the area is 52.5 m² and the width is 5 m. We need to determine the length.
We can rearrange the formula to solve for length by dividing both sides by the width:
l = A / w
Substituting the given values:
l = 52.5 m² / 5 m
l = 10.5 m
Therefore, the length of the rectangle is 10.5 m.
The solution to the real-world problem is that if the area of a rectangle is known to be 52.5 m² and the width is 5 m, the length is 10.5 m. This means that if you were to multiply the length by the width, you would get an area of 52.5 m². The length and width together determine the size of the rectangle.